Simple LED Circuit

Questions:

1. The resister slows down the current, making sure there is not too much going into the LED.

2. Using Ohm's Law (5 = I * 560) and solving for I we see that this current has .0089 Amps runing through it.

3.Using Ohm's Law (5 = .015 * R) and solving for R we see that for the circuit to have 15mA of current you would need A 333 Ohm resister.

4. All of the Voltage must be dropped, so if the LED drops 2.2 V, then the resister must drop 2.8 V.